JKSSB Recruitment 2025 Notification for 61 Posts: Apply Online Now

JKSSB Recruitment 2025

A significant career opportunity is knocking on your door. The Jammu and Kashmir Services Selection Board (JKSSB) has officially announced a new recruitment drive for 2025, inviting applications for 61 varied and important positions. This drive includes roles like Assistant Scientific Officer, Assistant Superintendent Jail, Computer Assistant, and Laboratory Attendant. This is a fantastic chance for qualified individuals to secure a stable and respected government job within the Jammu & Kashmir administration. If you have the required qualifications and a desire to contribute to the public sector, prepare your applications and get ready to apply for these promising roles.

Important Dates:

Notification Release Date22nd July 2025
Online Application Start4th August 2025
Application Deadline2nd September 2025

Job Details:

Government Jobs
Application ProcessOnline.
Organization NameJammu and Kashmir Services Selection Board (JKSSB).
Post NamesComputer Assistant, Laboratory Attendant, Assistant Scientific Officer, and Assistant Superintendent Jail.
Total Posts61.
Job LocationJammu & Kashmir.
Official Websitejkssb.nic.in.

Vacancy Details:

Post NameVacancies
Assistant Scientific Officer (Crime Scene)23
Assistant Scientific Officer (Documents)02
Assistant Scientific Officer (Chemistry and Toxicology)01
Assistant Superintendent Jail02
Computer Assistant01
Laboratory Attendant32
Total Posts61 Posts

JKSSB Recruitment 2025 Educational Qualification:

Candidates must possess specific qualifications for each post. This includes a Master’s Degree in relevant fields for Assistant Scientific Officer roles, a Graduation with a PG Diploma for Assistant Superintendent Jail, and a Graduation with a computer diploma for Computer Assistant. For the Laboratory Attendant post, a 10+2 with a Science stream is required. Please check the official notification for detailed requirements for each post.

JKSSB Recruitment 2025 Age Limit:

The age limits vary by category. For the Open Merit (OM) category, the maximum age is 40 years. There are relaxations for other categories: the maximum age is 43 years for SC, ST, EWS, and other reserved categories, 42 years for Physically Challenged Persons, and 48 years for Ex-Servicemen. Candidates in government service have a maximum age limit of 40 years.

JKSSB Recruitment 2025 Salary Details:

The salary structure for these posts is competitive and as per government norms. Assistant Scientific Officers and Assistant Superintendent Jail will be placed in Pay Level 6E (₹35,900 – ₹1,13,500). Computer Assistants will be in Level 4 (₹25,500 – ₹81,100), and Laboratory Attendants in SL 2 (₹15,900 – ₹50,400). The salary includes various allowances as applicable.

JKSSB Recruitment 2025 Selection Process:

The selection process for the JKSSB recruitment is a multi-stage process designed to find the most suitable candidates. The process will consist of the following stages:

  1. Written Examination.
  2. Document Verification.
  3. Interview.

Final selection will be based on the combined performance across these stages.

JKSSB Recruitment 2025 Application Fees:

The application fee for candidates under the UR/GEN category is ₹700. For candidates belonging to SC, ST, or EWS categories, the application fee is ₹600. The fee must be paid online during the application process.

JKSSB Recruitment 2025 How to Apply:

To apply for the JKSSB Recruitment 2025, follow these simple steps:

  1. First, visit the official JKSSB website at jkssb.nic.in.
  2. Navigate to the ‘Recruitment’ or ‘Careers’ section on the homepage.
  3. Find and open the notification for the “Computer Assistant, Laboratory Attendant and Other” posts.
  4. Read the eligibility criteria carefully before proceeding.
  5. If you are eligible, click on the application link to start filling out the form.
  6. Enter all your personal and educational details accurately.
  7. Upload scanned copies of any required documents, like your photograph and signature.
  8. Pay the application fee online and submit the form before the deadline of 2nd September 2025.
  9. Download and print a copy of your application for future reference.

Important Links:

Apply OnlineClick Here
Download Official NotificationClick Here
Join Telegram ChannelClick Here
Join WhatsApp ChannelClick Here

Frequently Asked Questions (FAQs):

What is the deadline for the JKSSB Recruitment 2025 application?

The last date to apply online for these positions is September 2, 2025.

How many total vacancies are available in this recruitment drive?

There are a total of 61 vacancies for various posts, including Assistant Scientific Officer and Laboratory Attendant.

What is the application fee for a general category applicant?

The application fee for candidates in the General (UR) category is ₹700/-.

What is the selection procedure for these JKSSB jobs?

The selection process includes a Written Examination, followed by Document Verification and an Interview.

What is the minimum qualification for the Laboratory Attendant post?

Candidates must have passed 10+2 with Science subjects from a recognized board to be eligible for the Laboratory Attendant post.

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Admin: Arghyadeep

Hi there, I'm an article writer. My experience spans five years. My main objective is to provide Indian job searchers with relevant job information. I cover many different subjects, including test results, government employment, private employment, and admit cards. Stay tuned for employment information that will assist you in finding a job and advancing your career.

Disclaimer: We make no claims to be a government recruiter organization or to have any connection to the government. All job-related information is sourced from different government websites. available in the public domain, from all credible sources. No government agency or individual is associated with the application. Only those seeking jobs are provided with the job information. Before submitting an application for any government position, kindly check the official government website once.

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